Indian wrestler Reetika Hooda lost a close quarter-final bout against Aiperi Medet Kyzy of Kyrgyzstan in the women's 76 kg freestyle category at the Paris Olympics on Saturday.
The wrestlers were locked 1-1 after six minutes of top-quality defensive wrestling but the Kyrgyz won having logged home the last equalising point as per rules.
Both wrestlers played a defensive game and the solitary point each was scored through passivity across the two periods.
Reetika will now wait for Kyzy to enter the final which will give her a shot at competing in the repechage round.
Earlier, Reetika displayed power and skill in equal measure while outclassing Hungarian Bernadett Nagy to enter the quarter-final of the women's 76 kg freestyle event on Saturday.
The referee stopped the contest with 29 seconds left in the second round as Reetika gained a 10-point lead with the final score reading 12-2 in favour of the Indian.
The burly Reetika gained upper-hand with 4-0 lead in the first round after getting an early leg-hold followed by a flip.
The Hungarian did get a couple of points but the Indian was unstoppable in the second round with a series of two pointers.
Aman Sehrawat Lost 4.6 Kg In 10 Hours...
CAS verdict on Vinesh's appeal set for Saturday night
Manpreet hails team's mental fortitude at Paris Games
PM Modi lauds grapple Aman's perseverance
Hockey Heroes Return Home