Top seed Victoria Azarenka charged ominously into the fourth round of the Indian Wells WTA tournament on Sunday while third-seeded Petra Kvitova made an unexpected early exit.
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The pony-tailed Azarenka, who was taken to a third set tiebreak in her opening match against Germany's Mona Barthel, broke Kuznetsova three times in the first set and twice in the second to sweep through.
Serving for the match at 5-2, she went 40-15 up before double-faulting but then sealed the win on the next point when her opponent's backhand flew long.
"I'm really pleased with that," a smiling Azarenka told reporters after dispatching Kuznetsova in one hour. "We have practised quite a few times, and I know she's a great player.
"She has so much experience and she's been a grand slam winner, so I knew she was gonna be dangerous.
"I really had to step it up from my last match," she added, referring to her three-hour battle with Barthel. "I'm glad I could perform much better... and show some good tennis."
Kvitova made a strong start against the 19-year-old McHale before errors began creeping into her game and she was bundled out of the tournament after a match lasting nearly two hours.
"She played very solid and she didn't have many mistakes," the Czech said. "She was moving very well, and she played a lot of shots to the back. My serve was not too good, too, so it was tough."
French Open champion Li Na beat fellow Chinese Zheng Jie 6-1, 6-3, her first victory over her compatriot in five career meetings.
In other matches, fifth seed Agnieszka Radwanska of Poland eased past Italy's Flavia Pennetta 6-4, 6-2 while Czech Klara Zakopalova was gifted a spot in the fourth round when Russian Vera Zvonareva became the latest victim of a viral infection affecting the tournament.
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